# Percentage Questions Set 2

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Questions on Percentage with solutions

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## Percentage Questions Set 2

Q.1. The population of a town is increased from 54500 to 58500 in one year. What is the percentage increase in the population?

1. 6.34%
2. 5.34%
3. 7.34%
4. 4.34%

Increase in population = 58500 - 54500 = 4000

∴ Percentage increase = (4000/54500) * 100 = 7.34 %

Q.2.  If the length of a rectangle is increased by 37.5% and its breadth is decreased by 20%, find the change in its area.

1. 10% increase
2. 13% decrease
3. 15% increase
4. 10% decrease

Area of rectangle = length * breadth
Length is Increased by 37.5% = 37(1/2)* 1/100 = 3/8
Breath is decreased by 20% = 1/5
l * b = Area
Old:       8 * 5 = 40
New:    11 * 4 = 44
Difference = 44-40 = 4
Original = 40
The percentage change is equal to (difference / original) * 100.
(4/40) *100 = 10% increase

Q.3. If 40% of 60% of 3/5 of a number is 504, what will be the 25% of 2/5 of that number?

1. 350
2. 150
3. 175
4. 230

Let the number is x.
(40/100) * (60/100) * (3/5) * x = 504
x= 3500
Now, (25/100)*(2/5)* 3500 = 350

Q.4. If a number x is 10% less than another number y and y is 10% more than 125, find the value of x.

1. 150
2. 125
3. 123.75
4. 175.25

We can write 10% increase as 11/10 that indicates +1 increase per 10
Similarly, we can write 10% decrease as 9/10 that indicates -1 decrease per 10
So, the required number = 125 * (11/10) * (9/10) = 123.75

Q.5. A student multiplied a number by 3/5 instead of 5/3. What is % error in calculation?

1. 54%
2. 64%
3. 74%
4. 84%

Let the number be x

error = 5x/3 - 3x/5 = 16x / 15

Error % = (16x/15) * (3/5x) * 100 = 64%

Q.6. A candidate who scores 30% fails by 5 marks, while another candidate who scores 40% marks gets 10 more than minimum passing marks. The minimum marks required to pass:

1. 50
2. 100
3. 45
4. 150

Let the total marks = x
So, (30/100)*x +5 = (40/100)*x - 10
(3/10)*x+5 = (4/10)*x -10
3x + 50 = 4x - 100
x = 150
Marks of Candidate A= 30% of 150 = 45
Candidate A fails by 5 marks.
So, minimum passing marks = 45 + 5=50

Q.7. In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was

1. 3100
2. 2400
3. 2700
4. 3400

Number of valid votes = 80% of 7500 = 6000. Valid votes polled by other candidate = 45% of 6000 = (45/100) * 6000 = 2700

Q.8. 65% of a number is more than its 36% by 58. What is 23% of the total number?

1. 46
2. 23
3. 66
4. 58

The difference between 65% and 36% of the number = 29%
Also, the difference between 65% and 36% = 58
Now, 29% is equal to 58.
So, 1% = 58/29 = 2 %
Then, 100% = 200
Now, 23% of 200 = 46
Hence, the required number is 46.

Q.9. In an election 2 candidates participate, 20% of the votes are declared invalid, and the winner gets 70% of the valid votes and wins the election by 3200 votes. Find the valid votes.

1. 10000
2. 8000
3. 5620
4. 12000

Then, 80 votes are valid only.
As per question, the winner gets = 80*(70/100) = 56 (valid votes),
So, the loser's votes = 80-56=24
Difference = 32, but acc to ques, it is 3200
i.e., 32 * 100 = 3200
Hence 80 * 100= 8000
So, we have to multiply 32 by 100 to make it equal to 3200.
So, 80 is also multiplied with 100.
Therefore, the total valid votes = 80 * 100= 8000

Q.10. Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get?

1. 47%
2. 57%
3. 67%
4. 77%